NSArray *keyArray =  [bigUglyDictionary allKeys];
	int count = [keyArray count];
	for (int i=0; i < count; i++) {
		NSDictionary *tmp = [bigUglyDictionary objectForKey:[ keyArray objectAtIndex:i]];
	}

	NSEnumerator *enumerator = [bigUglyDictionary keyEnumerator];
	id key;
	while ((key = [enumerator nextObject])) {
		NSDictionary *tmp = [bigUglyDictionary objectForKey:key];
	}

5 responses

1. 
   Riddhiman
   Posted September 28, 2010 at 18:09 | Permalink

   thanks, very helpful

   Reply
2. 
   Alan
   Posted January 19, 2011 at 02:11 | Permalink

   Or:

   
for( NSString *aKey in [bigUglyDictionary allKeys] )
{
// do something
}


   Or somewhat faster:

   
for( NSString *aKey in bigUglyDictionary )
{
// do something
}


   Or better yet, if your target OS supports blocks:
   
[bigUglyDictionary enumerateKeysAndObjectsUsingBlock: ^(id key, id obj, BOOL *stop) {
// do something with key and obj
}];


   Reply
3. 
   early childhood education salary
   Posted April 4, 2011 at 21:39 | Permalink

   you have got an ideal blog here! would you wish to make some invite posts on my weblog?

   Reply
4. 
   Roman
   Posted September 27, 2012 at 03:56 | Permalink

   Thanks (also Alan), that piece of code was very helpful.

   Reply
5. 
   Ambuj Shukla
   Posted January 12, 2013 at 11:40 | Permalink

   Sir I’m using NSString* name = (NSString *)ABRecordCopyCompositeName(person);
   to store contacts name from iphone contacts and I want that in an array so that it stores in array[0],array[1] and soon so that I can match it with some other array. Can u plz explain it to me.

   Reply